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In this article, you will learn and get code about how to create a program that finds average and percentage marks. The last program given here is the complete version of finding average and percentage marks of a student. In that program, number of subject and maximum marks is also decided by user.

The question is, **write a program in C, that asks from user to enter marks obtained in 5 subjects and prints average
mark as output**. So the answer to this question is given below:

#include<stdio.h> #include<conio.h> int main() { int i; float mark, sum=0, avg; printf("Enter Marks obtained in 5 Subjects: "); for(i=0; i<5; i++) { scanf("%f", &mark); sum = sum+mark; } avg = sum/5; printf("\nAverage Mark = %0.2f", avg); getch(); return 0; }

This program was compiled and executed in **Code::Blocks** IDE. This is the first snapshot of sample run:

Now supply marks obtained in 5 subjects as input say **76, 87, 98, 70, 82** and press **ENTER** key to see the
average mark of student as shown in the second snapshot of sample run given below:

Here are some of the main steps used in above program:

- Declare a variable say
**i**of**int**type to work with it in loop - Declare another three variables say
**mark, sum**, and**avg**of type**float** - Here these three variables are declared as float, because to hold any value that contains decimal
- Initialize 0 to the variable
**sum**in declaration part - Now here we have applied a
**for**loop that runs 5 times - In each run, program scans mark value and adds it to
**sum**variable - So after exiting from the loop, we have a
**sum**variable that holds sum of all the 5 marks entered by user at run-time - Just divide
**sum**with 5, to find average mark of given 5 numbers - Print the value of
**avg**as output. That it

To learn about **loop** (used in previous program) in detail, refer to for loop in C
tutorial. Let's move on to next program.

The question is, **write a program in C, that asks from user to enter marks obtained in 5 subjects (out of 100)
and find the percentage marks of student**. The answer to this question is given below:

To calculate percentage marks of a student in C programming, you have to ask from user to enter marks obtained in some
number of subjects (5 subjects here, i.e Physics, Chemistry, Math, CS, and English). Place summation of 5 marks in a variable
say **sum** and place **sum/5** in a variable say **avg**. Simply print **avg** as the result on output.

#include<stdio.h> #include<conio.h> int main() { int i; float mark, sum=0, perc; printf("Enter Marks obtained in 5 Subjects (Out of 100): "); for(i=0; i<5; i++) { scanf("%f", &mark); sum = sum+mark; } perc = (sum/500)*100; printf("\nPercentage Mark = %0.2f%c", perc, 37); getch(); return 0; }

This program will produce the output as shown in the snapshot given below:

Most of the code written in this program is almost same as of previous program except, here we have used **%c** format
specifier with 37 as its value. Because, **%c** format specifier is used to print character, and the ASCII value of
**%** character is 37. So to print **%** sign on output screen after the percentage value, we have used its ASCII
value as shown in the above output.

The question is, **write a program in C that asks from user to enter marks obtained and find average and percentage mark
value. Here subject count and maximum marks must be entered by user.** The answer to this question is given below.

This is the complete version of calculating average and percentage marks program in C. Here the number of subject and maximum mark is decided by user. Let's have a look at it:

#include<stdio.h> #include<conio.h> int main() { int i, n, max; float mark, sum=0, avg, perc; printf("How many Subject runs in your Institute ? "); scanf("%d", &n); printf("\nEnter Maximum Mark of Subject: "); scanf("%d", &max); printf("\nEnter Marks obtained in %d Subjects (Out of %d): ", n, max); for(i=0; i<n; i++) { scanf("%f", &mark); sum = sum+mark; } avg = sum/n; perc = (sum/(n*max))*100; printf("\nAverage Mark = %0.2f", avg); printf("\nPercentage Mark = %0.2f%c", perc, 37); getch(); return 0; }

The snapshot given below shows the initial output of this program:

And the snapshot given below shows the final output of this program after supplying total number of subject runs in institute, maximum marks, and marks obtained in all subject.

Let's understand the above program (with its output) by the example given below:

- User enters
**6**as first question, that is**How many Subject runs in your Institute ?**. So**n**holds its value as 6 - User enters
**50**as second question. So the variable**max**has its value as**50** - Now user enters marks obtained in 6 subjects one by one. And the summation operation performed on each scan like this:
- On first scan, user enters
**42**, so**sum+mark**or**0+42**(0 is initial value of**sum**) gets initialized to**sum** - Now
**sum**contains 42 as its value - On second scan, user enters
**46**, so**42+46**or**88**gets initialized to**sum** - Now
**sum**contains 88 as its value - On third scan, user enters
**40**, so**88+40**gets initialized to**sum** - Now
**sum**contains**128**as its value - On fourth scan, user enters
**38**, so**128+38**or**166**gets initialized to**sum** - Now
**sum**contains**166**as its value - On fifth scan, user enters
**41**, so**166+41**or**207**gets initialized to**sum** - Now
**sum**contains**207**as its value - On sixth scan, user enters
**39**, so**207+39**or**246**gets initialized to**sum** - Now
**sum**contains**246**as its value

- On first scan, user enters
- As of now,
**sum**contains**246**,**n**contains 6, and**max**contains**50** - So,
**sum/n**or**246/6**or**41**gets initialized to**avg**variable - And,
**(sum/(n*max))*100**or**(246/(6*50))*100**or**(246/300)*100**or**82**gets initialized to**perc**variable - Now simply print the value of
**avg**and**perc**variable as output of**Average Mark**and**Percentage Mark** **%0.2f**is used to print value upto 2 decimal places only. And**%c**with 37, is used to print**%**sign. Because**37**is the ASCII value of**%**sign. That's it

- C++ Calculate Average and Percentage Marks
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